You've just learned how to multiply two-digit numbers. Now we're going to work a multiplication problem that has a three-digit number on top. Look at this problem:

Problems like this aren't that hard to solve if we take it a step at a time. First, we work 4 times 3. What's the answer? The answer equals 12. Write the 2 below the equal bar. Then we regroup (carry) the 1 and place it on top of the 6 in the tens place (tens column). Here's how it will look:

Next we multiply 6 times 3. What do we get? We get 18. But we have to add the regrouped digit, 1. We'll have 19. Write the 9 and regroup the 1.

Now we multiply 3 times 3. What's the answer? It's 9. Add the 1 we regrouped. So we get 10.

Now we multiply by 8. Before we do that, we have to do two things. First, cross out the regrouped numbers. Then write 0 in the ones place (ones column) to begin your second answer.

The next multiplication is 4 times 8. That's 32. What part of the 32 do we regroup? We write the 2 and regroup the 3.

Next is 6 times 8. That's 48 plus the regrouped 3. Now we have 51. Let's write the 1 and regroup the 5.

Lastly, we multiply 3 times 8, which gives us 24. How many is 24 plus the 5 we regrouped? The answer is 29.

Now we add to find the product, or answer: 1,092 + 29,120 = 30,212. Remember, multiplication with two or more digits is easy if you work one step at a time.





