Sometimes, when the answer to a problem in one place value has two digits, we need to regroup (carry) one digit to the next place value.
Let's try this:
The problem in the ones place (ones column) is 2 times 7. The answer equals 14, a two-digit number. We can only fit one digit below the equal bar, so where does the other digit go?
We write 4 below the equal bar and regroup 1 to the tens place (tens column).
Here's another way to look at it: We are solving for 2 ones times 7 ones. The answer equals 14, or 1 ten and 4 ones. We write 4 ones and regroup 1 ten to the next place value.
Next, the problem in the tens place is 5 times 7, which equals 35. Then we add the 1 regrouped to the answer in the tens place.
35 + 1 = 36
We write 6 tens below the equal bar and regroup 3 to the hundreds places (hundreds column).
The problem in the hundreds place is 8 times 7. The answer equals 56. We add the 3 we regrouped, giving us 59.
This is the last place value to solve for, so we write down the whole answer, 59. Our final product (answer) equals 5,964.
Remember, when the answer is a two-digit number, regroup the tens digit to the next place value. When you are solving for the problem in the final place value, write down both digits.
