You've learned how to multiply two-digit numbers where you must regroup (carry) once. Now we'll move on to a higher level. This time we're going to work column multiplication where you have to regroup twice. You read it right! We're going to regroup two time­s.

Let's start by working this multiplication problem:

Remember, to solve this problem we have to regroup twice. So how do we do it? First, we multiply the digits in the ones place (ones column): 6 times 8 equals what number? The answer is 48. Write 8 below the equal bar and regroup the 4.

Next, we multiply 2 times 8. What's the answer? The answer equals 16. Then we add the 4 we regrouped. The answer is 20. Write it down.

Before we do the next multiplication, we need to cross out the number we regrouped so we don't get confused when we regroup again.

Remember to start by adding a zero in the ones place below the equal bar. Now we multiply for the tens place (tens column): 6 times 3. What's the answer? It's 18. Write the 8 and regroup the 1. Now we multiply 2 time­s 3. That's 6. Add the number that we regrouped. What number did we regroup? It's 1. So 6 plus 1 equals 7(6 + 1 = 7).

Finally, we add 208 + 780 to get the product, or answer, which is 988, for the multiplication problem.

Remember, when you multiply by a two-digit number, cross out any digit you regrouped before you multiply by the tens digit.