We've already learned how to multiply a two-digit number by a single-digit number. But what if our problem looks like this?

This problem requires regrouping (carrying). When we work multiplication problems like this one, we're actually working two multiplication problems.

First, we work the problem in the ones place (ones column):

What answer do we get? The product, or answer, equals 15.

Second, we work the problem in the tens place (tens column):

What is 6 tens times 3? The product equals 18 tens, or 180. If we add our two products, 15 and 180, we get 195. Therefore, 65 times 3 equals 195.

If we want to work the same problem faster, we have to regroup.

Again, the problem for the ones place is 5 times 3. This equals 15, right? Our answer has two digits, so we regroup the tens digit of 15 to the tens place like this:

Now, to work the tens place, we multiply and then we add. What is 6 tens times 3? The answer is 18 tens. Then we add the 1 ten we regrouped, and we now have 19 tens.

The answer is still 195. Let's practice again with this new problem:

The problem for the ones place is 6 times 4. So what's the answer? We get 24. We write 4 at the bottom and regroup the tens digit to the tens place like this:

To work the tens place, we multiply 3 tens by 4. We get 12 tens and then add the 2 tens we regrouped. So what do we get? We have 14 tens. Therefore, the product for 36 times 4 equals 144.