When we work short division problems with three-digit numbers and no remainders, we divide each digit of the greater (larger) number by the lesser (smaller) number.
In the problem above, our greater number is 468 and our lesser number is 2. What is the hundreds digit of 468? It's 4. So we divide 4 by 2 to equal 2 (4 ÷ 2 = 2). Write 2 above the 4 in the hundreds place.
Then we divide the tens digit by 2. Our problem is 6 divided by 2, which equals 3 (6 ÷ 2 = 3). We write 3 above the 6 in the tens place.
Now let's solve for the ones digit of 468. What is the ones digit? It's 8, so we divide 8 by 2 to get our answer, which equals 4 (8 ÷ 2 = 4). Write 4 above the 8 in the ones place.
Now we have our missing lesser number in this number family. The missing number is 234.
Let's solve another problem:
The hundreds digit of our greater number is 9, so we divide it by the lesser number. So 9 divided by 3 equals 3 (9 ÷ 3 = 3). We place 3 above the 9 in the hundreds place.
Next, we divide the tens digit. So 6 divided by 3 equals 2 (6 ÷ 3 = 2). We place 2 above the 6 in the tens place.
Finally, we go to the ones digit, which is 3. What is 3 divided by 3? It's 1 (3 ÷ 3 = 1).
Let's place 1 above the 3 in the ones place so we get our quotient, or answer. Our quotient equals 321.
